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PSAT/NMSQT Math / LEVEL 3 · DIFFICULTY 3/5

Data Analysis: Evidence & Predictions

Use data displays, probability, sampling, rates and units to reason carefully.

6 stages · 48 practice problems · two 12-question assessment forms

Choose a node to explore its lesson.

  1. 1MINI QUEST PSAT 3.1Standard Deviation, Center & OutliersRead the lesson
  2. 2MINI QUEST PSAT 3.2Dot Plots, Histograms & Frequency TablesRead the lesson
  3. 3MINI QUEST PSAT 3.3Scatterplots & Lines of Best FitRead the lesson
  4. 4MINI QUEST PSAT 3.4Two-Way Tables & Conditional ProbabilityRead the lesson
  5. 5MINI QUEST PSAT 3.5Samples, Population Estimates & LimitsRead the lesson
  6. 6MINI QUEST PSAT 3.6Rates, Units & Percent ChangesRead the lesson
  7. LEVEL CHECKCastle challenge

    12 questions across this level.

    Sign in for the level check →

STAGE PSAT 3.1 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Standard Deviation, Center & Outliers

The idea to remember

Adding a constant shifts the mean without changing standard deviation. Multiplying by c scales standard deviation by ∣c∣\displaystyle \left|c\right|∣c∣.

Remember with 2 flashcards →

Goal: Compare variability, predict how shifts and scaling affect spread, and distinguish effects on mean and median.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

Move the dots. Watch the spread.

This is an exploration example. Its values are separate from your practice question.

01234567891011mean

Values: 2, 3, 3, 4, 4, 4, 5, 5, 6. Mean = 4; population standard deviation ≈ 1.15.

Shifting changes the center but keeps the spread. Stretching around the center changes spread but keeps the mean.

Make sense of the idea

Standard deviation describes how far values typically lie from their mean. A tightly packed set has smaller standard deviation than a more spread-out set with the same center. You usually can compare without calculating a formula.

Choose a method

Adding the same constant to every value shifts the mean and median but leaves standard deviation unchanged. Multiplying every value by c multiplies standard deviation by ∣c∣\displaystyle \left|c\right|∣c∣.

Check and interpret

An extreme outlier can pull the mean strongly. The median depends on ordered position and is often less affected. Always compare center and spread separately.

WORKED EXAMPLE 1

Compare A:6\displaystyle A : 6A:6, 7, 8; B:4\displaystyle B : 4B:4, 7, 10. Which has greater standard deviation? Enter 1 for A, 2 for B, or 3 if equal.

  1. Both means are 7. A has distances 1, 0, 1; B has distances 3, 0, 3.
  2. B is more spread out and has 3 times the standard deviation. Enter 2.

2

WORKED EXAMPLE 2

Five commute times are 6, 7, 8, 9, 10. Only the largest value is replaced by 56. What is the new median?

  1. The third value is still 8.
  2. So the median remains 8, although the mean and spread increase.

8

Common pitfalls

Possible mix-up: A larger mean always means more spread.

Shifting all observations changes the mean without changing spread.

Possible mix-up: Adding 5 to each value adds 5 to the standard deviation.

All distances from the mean stay the same.

Explain it to yourself

In standard deviation, center & outliers, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in standard deviation, center & outliers. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    Compare A:4\displaystyle A : 4A:4, 5, 6; B:2\displaystyle B : 2B:2, 5, 8. Which has greater standard deviation? Enter 1 for A, 2 for B, or 3 if equal.

    Practise this exact problem →
  2. Problem 2

    Every observation in a data set is increased by 9. The original standard deviation is 2. What is the new standard deviation?

    Practise this exact problem →
  3. Problem 3

    A transformation multiplies every data value by 3. If the original standard deviation is 2, what is the new standard deviation?

    Practise this exact problem →
  4. Problem 4

    A sorted data set is 3, 4, 5, 6, 7. Only the largest value is replaced by 53. What is the new median?

    Practise this exact problem →
  5. Problem 5New context

    Two teams record A:5\displaystyle A : 5A:5, 6, 7; B:3\displaystyle B : 3B:3, 6, 9. Which has greater standard deviation? Enter 1 for A, 2 for B, or 3 if equal.

    Practise this exact problem →
  6. Problem 6New context

    Every temperature reading is increased by 10. The original standard deviation is 3. What is the new standard deviation?

    Practise this exact problem →
  7. Problem 7New context

    A measurement unit conversion multiplies every data value by 3. If the original standard deviation is 3, what is the new standard deviation?

    Practise this exact problem →
  8. Problem 8New context

    Five commute times are 4, 5, 6, 7, 8. Only the largest value is replaced by 54. What is the new median?

    Practise this exact problem →
Open stage PSAT 3.1 in the student workspace →

STAGE PSAT 3.2 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Dot Plots, Histograms & Frequency Tables

The idea to remember

Dot plots retain individual values; histograms group intervals and may not identify an exact median or mean.

Remember with 2 flashcards →

Goal: Read frequencies and intervals, locate medians from counts, and distinguish what grouped data can and cannot tell you.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

Same observations, different displays

This is an exploration example. Its values are separate from your practice question.

01234567891011mean

Values: 2, 3, 3, 4, 4, 4, 5, 5, 6. Mean = 4; population standard deviation ≈ 1.15.

Shifting changes the center but keeps the spread. Stretching around the center changes spread but keeps the mean.

A histogram groups these observations into intervals
IntervalFrequency
0 ≤ value < 43
4 ≤ value < 86
8 ≤ value < 120

Moving a value across an interval boundary changes its bin. The histogram gives counts, but hides exact positions within each bin.

Make sense of the idea

In a dot plot each dot is one observation. Repeated values form stacks. A frequency table records the same information with counts.

Choose a method

A histogram groups numerical values into nonoverlapping intervals. The height gives frequency, not the data value. Read interval endpoints carefully: [10,20) includes 10 but excludes 20.

Check and interpret

Use cumulative counts to locate the median. From grouped counts alone you can identify a median interval, but generally cannot reconstruct an exact mean or each original observation.

WORKED EXAMPLE 1

A frequency table lists score 4:2\displaystyle 4 : 24:2 observations; score 5:3\displaystyle 5 : 35:3 observations; score 6:1\displaystyle 6 : 16:1 observation. What is the mean score?

  1. The total count is 2+3+1=6\displaystyle 2 + 3 + 1 = 62+3+1=6.
  2. The sum is 2×4+3×5+6=29\displaystyle 2 \times 4 + 3 \times 5 + 6 = 292×4+3×5+6=29, so the mean is 296\displaystyle \frac{29}{6}629​.

296\displaystyle \frac{29}{6}629​

WORKED EXAMPLE 2

A delivery-time histogram contains 8 values in [0,10), 10 in [10,20), and 1 in [20,30). Can the EXACT mean be determined from these counts alone? Enter 1 for yes or 0 for no.

Histogram: intervals include the left endpoint and exclude the right
Frequency80101012030Value
  1. Different raw data sets can produce exactly these same bin counts.
  2. Their sums, and hence means, can differ. The exact mean is not determined; enter 0.

0

Common pitfalls

Possible mix-up: A bar height is the measurement value.

The horizontal axis gives values or intervals; the height gives frequency.

Possible mix-up: A histogram gives an exact value for each observation.

Grouping loses information within each bin.

Explain it to yourself

In dot plots, histograms & frequency tables, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in dot plots, histograms & frequency tables. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    A frequency table lists score 2:2\displaystyle 2 : 22:2 observations; score 3:3\displaystyle 3 : 33:3 observations; score 4:1\displaystyle 4 : 14:1 observation. What is the mean score?

    Practise this exact problem →
  2. Problem 2

    A dot plot has 2 dots at 3, 3 at 5, and 2 at 8. What is the median?

    Practise this exact problem →
  3. Problem 3

    A histogram has 4 observations in [0,10), 6 in [10,20), and 8 in [20,30). How many observations are at least 10?

    Histogram: intervals include the left endpoint and exclude the right
    Frequency4061082030Value
    Practise this exact problem →
  4. Problem 4

    A histogram contains 5 values in [0,10), 7 in [10,20), and 1 in [20,30). Can the EXACT mean be determined from these counts alone? Enter 1 for yes or 0 for no.

    Histogram: intervals include the left endpoint and exclude the right
    Frequency5071012030Value
    Practise this exact problem →
  5. Problem 5New context

    A reading log⁡\displaystyle \operatorname{log}log lists score 3:2\displaystyle 3 : 23:2 observations; score 4:3\displaystyle 4 : 34:3 observations; score 5:1\displaystyle 5 : 15:1 observation. What is the mean score?

    Practise this exact problem →
  6. Problem 6New context

    A dot plot of daily visits has 2 dots at 4, 3 at 6, and 2 at 9. What is the median?

    Practise this exact problem →
  7. Problem 7New context

    A histogram of wait times has 5 observations in [0,10), 7 in [10,20), and 9 in [20,30). How many observations are at least 10?

    Histogram: intervals include the left endpoint and exclude the right
    Frequency5071092030Value
    Practise this exact problem →
  8. Problem 8New context

    A delivery-time histogram contains 6 values in [0,10), 8 in [10,20), and 1 in [20,30). Can the EXACT mean be determined from these counts alone? Enter 1 for yes or 0 for no.

    Histogram: intervals include the left endpoint and exclude the right
    Frequency6081012030Value
    Practise this exact problem →
Open stage PSAT 3.2 in the student workspace →

STAGE PSAT 3.3 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Scatterplots & Lines of Best Fit

The idea to remember

A fitted line predicts an average trend. Residual equals observed minus predicted, and extrapolation can be unreliable.

Remember with 2 flashcards →

Goal: Describe scatterplot trends, use a fitted line to predict, interpret residuals, and compare linear with exponential patterns.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

A fitted line follows the pattern

Five observations, with a least-squares fitted line y=1.2 x+1\displaystyle y = 1.2\, x + 1y=1.2x+1. Drag the input control to predict a value.

0012243648510612714816xy

Predicted y = 4.6. This input is within the observed range: interpolation.

At x=3\displaystyle x = 3x=3, the observed value is 4 and the prediction is 4.6. Residual = 4−4.6=−0.6\displaystyle 4 - 4.6 = -0.64−4.6=−0.6: that dot is below the fitted line.

Read the paired observations
xObserved yPredicted y
122.2
243.4
344.6
465.8
577

Make sense of the idea

Each scatterplot point is one paired observation (x,y). A positive trend rises overall as x increases; it does not require every point to lie exactly on a line.

Choose a method

A fitted line follows the overall pattern and balances deviations; it need not pass through the origin or every point. In y = mx + b, m is the predicted change in y for one extra x-unit.

Check and interpret

A residual is observed y minus predicted y. Prediction within the observed x-range is interpolation; going outside it is extrapolation and needs caution. Equal differences suggest a linear pattern; equal positive ratios suggest an exponential one.

WORKED EXAMPLE 1

A fitted line is y=4 x+7\displaystyle y = 4\, x + 7y=4x+7. What y-value does it predict at x=4\displaystyle x = 4x=4?

  1. ŷ = 4×4+7\displaystyle 4 \times 4 + 74×4+7.
  2. The predicted value is 23; an actual observation may differ.

23

WORKED EXAMPLE 2

A scatterplot model was built using x-values from 6 to 16. Predicting at x=26\displaystyle x = 26x=26 is which type? Enter 1 for interpolation or 2 for extrapolation.

  1. 26 is larger than the observed maximum 16.
  2. This is extrapolation (2); the same trend may not continue outside the observed range.

2

Common pitfalls

Possible mix-up: A best-fit line must pass through every point.

Real data usually scatter around it.

Possible mix-up: A positive residual means the model predicted too much.

It means the observation is above the prediction.

Explain it to yourself

In scatterplots & lines of best fit, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in scatterplots & lines of best fit. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    A fitted line is y=2 x+5\displaystyle y = 2\, x + 5y=2x+5. What y-value does it predict at x=4\displaystyle x = 4x=4?

    Practise this exact problem →
  2. Problem 2

    A fitted model is y=3 x+6\displaystyle y = 3\, x + 6y=3x+6. At x=4\displaystyle x = 4x=4, the observed y is 20. Find the residual (observed minus predicted).

    Practise this exact problem →
  3. Problem 3

    A data table has x=0\displaystyle x = 0x=0,1,2,3 and y=2\displaystyle y = 2y=2,4,8,16. Which model fits this exact pattern: 1 for linear or 2 for exponential?

    Paired observations from this question
    08160123xy
    x0123
    y24816
    Practise this exact problem →
  4. Problem 4

    A fitted line was built using x-values from 3 to 13. Predicting at x=23\displaystyle x = 23x=23 is which type? Enter 1 for interpolation or 2 for extrapolation.

    Practise this exact problem →
  5. Problem 5New context

    A scatterplot of study time and practice scores has fitted line y=3 x+6\displaystyle y = 3\, x + 6y=3x+6. What y-value does it predict at x=4\displaystyle x = 4x=4?

    Practise this exact problem →
  6. Problem 6New context

    A delivery-time model is y=3 x+7\displaystyle y = 3\, x + 7y=3x+7. At x=4\displaystyle x = 4x=4, the observed y is 21. Find the residual (observed minus predicted).

    Practise this exact problem →
  7. Problem 7New context

    A growth record has x=0\displaystyle x = 0x=0,1,2,3 and y=3\displaystyle y = 3y=3,6,12,24. Which model fits this exact pattern: 1 for linear or 2 for exponential?

    Paired observations from this question
    012240123xy
    x0123
    y361224
    Practise this exact problem →
  8. Problem 8New context

    A scatterplot model was built using x-values from 4 to 14. Predicting at x=24\displaystyle x = 24x=24 is which type? Enter 1 for interpolation or 2 for extrapolation.

    Practise this exact problem →
Open stage PSAT 3.3 in the student workspace →

STAGE PSAT 3.4 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Two-Way Tables & Conditional Probability

The idea to remember

For a conditional proportion, divide the intersection count by the count of the stated conditioning group.

Remember with 2 flashcards →

Goal: Use a two-way frequency table to choose the correct denominator for joint, marginal and conditional probabilities.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

First choose who can be selected

How 20 club members travel
ClubBusWalkTotal
A6410
B3710
Total91120

Only the 10 club A members can be selected. Probability = 610\displaystyle \frac{6}{10}106​.

The phrase “given” changes the denominator. The table itself has not changed.

Make sense of the idea

A two-way table classifies each person by two categories. Each inner cell belongs to one row and one column. Row and column totals are marginal counts.

Choose a method

A joint probability asks for both properties: use the intersection cell divided by the grand total. A marginal probability uses a row or column total divided by the grand total.

Check and interpret

A conditional probability restricts the sample space first. “Given the person is in Group A” means divide by the Group A total, not by all people. Reverse conditions generally give different probabilities.

WORKED EXAMPLE 1

A two-way table gives club A: bus 4, walk 6; club B: bus 5, walk 7. Given a student is in club A, what is the probability they take the bus? Enter a fraction.

The counts from this question
ClubBusWalkTotal
A4610
B5712
Total91322
  1. Club A contains 10 students and 4 take the bus.
  2. The conditional probability is 410\displaystyle \frac{4}{10}104​.

410\displaystyle \frac{4}{10}104​

WORKED EXAMPLE 2

A transport survey gives club A: bus 8, walk 6; club B: bus 5, walk 7. Given that a student takes the bus, what is the probability they are in club A?

The counts from this question
ClubBusWalkTotal
A8614
B5712
Total131326
  1. The bus group has 13 students, of whom 8 are in club A.
  2. P(A given bus) = 813\displaystyle \frac{8}{13}138​.

813\displaystyle \frac{8}{13}138​

Common pitfalls

Possible mix-up: Every probability uses the grand total.

Conditional probability uses the total of the given group.

Possible mix-up: P(A given B) equals P(B given A).

Their denominators differ unless special counts happen to make them equal.

Explain it to yourself

In two-way tables & conditional probability, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in two-way tables & conditional probability. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    A two-way table gives club A: bus 2, walk 4; club B: bus 3, walk 5. Given a student is in club A, what is the probability they take the bus? Enter a fraction.

    The counts from this question
    ClubBusWalkTotal
    A246
    B358
    Total5914
    Practise this exact problem →
  2. Problem 2

    A two-way table gives club A: bus 3, walk 4; club B: bus 6, walk 5. A student is selected from ALL students. What is the probability of club B AND walking?

    The counts from this question
    ClubBusWalkTotal
    A347
    B6511
    Total9918
    Practise this exact problem →
  3. Problem 3

    A two-way table gives club A: bus 4, walk 2; club B: bus 3, walk 6. What is the probability a randomly selected student walks, regardless of club?

    The counts from this question
    ClubBusWalkTotal
    A426
    B369
    Total7815
    Practise this exact problem →
  4. Problem 4

    A two-way table gives club A: bus 5, walk 3; club B: bus 2, walk 4. Given that a student takes the bus, what is the probability they are in club A?

    The counts from this question
    ClubBusWalkTotal
    A538
    B246
    Total7714
    Practise this exact problem →
  5. Problem 5New context

    A survey gives club A: bus 3, walk 5; club B: bus 4, walk 6. Given a student is in club A, what is the probability they take the bus? Enter a fraction.

    The counts from this question
    ClubBusWalkTotal
    A358
    B4610
    Total71118
    Practise this exact problem →
  6. Problem 6New context

    A travel survey gives club A: bus 4, walk 5; club B: bus 7, walk 6. A student is selected from ALL students. What is the probability of club B AND walking?

    The counts from this question
    ClubBusWalkTotal
    A459
    B7613
    Total111122
    Practise this exact problem →
  7. Problem 7New context

    A school survey gives club A: bus 5, walk 3; club B: bus 4, walk 7. What is the probability a randomly selected student walks, regardless of club?

    The counts from this question
    ClubBusWalkTotal
    A538
    B4711
    Total91019
    Practise this exact problem →
  8. Problem 8New context

    A transport survey gives club A: bus 6, walk 4; club B: bus 3, walk 5. Given that a student takes the bus, what is the probability they are in club A?

    The counts from this question
    ClubBusWalkTotal
    A6410
    B358
    Total9918
    Practise this exact problem →
Open stage PSAT 3.4 in the student workspace →

STAGE PSAT 3.5 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Samples, Population Estimates & Limits

The idea to remember

Random sampling supports population estimates. A convenience sample can be biased, even if it is large.

Remember with 2 flashcards →

Goal: Estimate population counts or totals from random sample statistics and explain why the estimate is not an exact census.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

Make sense of the idea

A population is the complete group of interest. A sample is a subset. A random sample can help estimate a population proportion or mean, but it still has sampling variability.

Choose a method

Estimate a population count by sample proportion × population size. Estimate a population total by sample mean × population size. Keep units consistent.

Check and interpret

A larger random sample usually gives a more stable estimate, but size alone does not repair a biased selection method. A survey only of volunteers at a sports club need not represent the whole school.

WORKED EXAMPLE 1

A researcher randomly samples 50 of 1100 residents; 12 use an audiobook service. Use the sample proportion to estimate the number of users in the population.

  1. The sample proportion is 1250\displaystyle \frac{12}{50}5012​.
  2. The estimated count is (1250)×1100=264\displaystyle \left(\frac{12}{50}\right) \times 1100 = 264(5012​)×1100=264. This is an estimate, not a census.

264

WORKED EXAMPLE 2

A school report estimates 23%\displaystyle 23\%23% of a population prefers option A, using a random sample rather than a census. Must EXACTLY 23%\displaystyle 23\%23% of the population prefer A? Enter 1 for yes or 0 for no.

  1. The 23%\displaystyle 23\%23% figure is a sample-based estimate.
  2. Sampling variability means the population proportion need not equal it exactly. Enter 0.

0

Common pitfalls

Possible mix-up: An estimated count is the exact count.

Random sampling still varies; only measuring the full population gives a census count.

Possible mix-up: A large biased sample must be representative.

Who is selected matters as well as how many.

Explain it to yourself

In samples, population estimates & limits, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in samples, population estimates & limits. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    A researcher randomly samples 50 of 1000 residents; 10 use an audiobook service. Use the sample proportion to estimate the number of users in the population.

    Practise this exact problem →
  2. Problem 2

    A random sample has mean mass 8 grams. There are 120 parcels in the population. Estimate the total mass in grams.

    Practise this exact problem →
  3. Problem 3

    For a schoolwide estimate, 30 volunteers from a sports club are surveyed. Does this method give a random sample of the WHOLE school? Enter 1 for yes or 0 for no.

    Practise this exact problem →
  4. Problem 4

    A sample report estimates 20%\displaystyle 20\%20% of a population prefers option A, using a random sample rather than a census. Must EXACTLY 20%\displaystyle 20\%20% of the population prefer A? Enter 1 for yes or 0 for no.

    Practise this exact problem →
  5. Problem 5New context

    A town library randomly samples 50 of 1050 residents; 11 use an audiobook service. Use the sample proportion to estimate the number of users in the population.

    Practise this exact problem →
  6. Problem 6New context

    A random sample of parcels has mean mass 9 grams. There are 130 parcels in the population. Estimate the total mass in grams.

    Practise this exact problem →
  7. Problem 7New context

    To estimate schoolwide exercise habits, 31 volunteers from a sports club are surveyed. Does this method give a random sample of the WHOLE school? Enter 1 for yes or 0 for no.

    Practise this exact problem →
  8. Problem 8New context

    A school report estimates 21%\displaystyle 21\%21% of a population prefers option A, using a random sample rather than a census. Must EXACTLY 21%\displaystyle 21\%21% of the population prefer A? Enter 1 for yes or 0 for no.

    Practise this exact problem →
Open stage PSAT 3.5 in the student workspace →

STAGE PSAT 3.6 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS

Rates, Units & Percent Changes

The idea to remember

Convert units before comparing rates. Percentage changes use the original value as their denominator.

Remember with 2 flashcards →

Goal: Track units in rates, square or cube length-conversion factors, and distinguish relative percent from percentage points.

Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.

Make sense of the idea

A conversion factor equals one in different units. Multiply so unwanted units cancel. A length conversion factor must be squared for area and cubed for volume.

Choose a method

A percent change is measured relative to a base: new = old × (1 ± rate). To recover the old amount, divide the new amount by the factor.

Check and interpret

Percentage points subtract two percentages directly. Relative percent change divides that difference by the old percentage. Successive percent changes multiply their factors.

WORKED EXAMPLE 1

Convert 4 m2\displaystyle 4\, m^{2}4m2 to cm². Enter only the number.

  1. 1 m2=1002\displaystyle 1\, m^{2} = 100^{2}1m2=1002 cm² = 10,000 cm².
  2. 4 m2=40000\displaystyle 4\, m^{2} = 400004m2=40000 cm².

40000

WORKED EXAMPLE 2

A survey approval rate rises from 23%\displaystyle 23\%23% to 33%\displaystyle 33\%33%. What is the increase in PERCENTAGE POINTS?

  1. 33−23=10\displaystyle 33 - 23 = 1033−23=10 percentage points.
  2. The relative percent increase would instead be (1023)×100%\displaystyle \left(\frac{10}{23}\right) \times 100\%(2310​)×100%, which is a different question.

10

Common pitfalls

Possible mix-up: One square meter is 100 square centimeters.

Each side contributes a factor of 100; it is 10,000 cm².

Possible mix-up: Increasing then decreasing by the same percent restores the original.

The second change uses a different base. Multiply both factors.

Explain it to yourself

In rates, units & percent changes, what information determines your method, and how can you check whether your result fits the original conditions?

Discuss together

Ask your learner to explain one representation and check the conditions in rates, units & percent changes. Compare independent answers with hinted attempts and application problems. A completed lesson is not a PSAT score prediction.

Preview the eight practice prompts
  1. Problem 1

    Convert 2 m2\displaystyle 2\, m^{2}2m2 to cm². Enter only the number.

    Practise this exact problem →
  2. Problem 2

    Convert 2 cm³ to mm³. Enter only the number.

    Practise this exact problem →
  3. Problem 3

    An item costs $80 after a 20%\displaystyle a\, 20\%a20% discount. What was its original price in dollars?

    Practise this exact problem →
  4. Problem 4

    A percentage rises from 20%\displaystyle 20\%20% to 30%\displaystyle 30\%30%. What is the increase in PERCENTAGE POINTS?

    Practise this exact problem →
  5. Problem 5New context

    A garden covers 3 m2\displaystyle 3\, m^{2}3m2. How many square centimeters is that?

    Practise this exact problem →
  6. Problem 6New context

    A container holds 3 cm³. How many cubic millimeters is that?

    Practise this exact problem →
  7. Problem 7New context

    A jacket costs $88 after a 20%\displaystyle a\, 20\%a20% discount. What was its original price in dollars?

    Practise this exact problem →
  8. Problem 8New context

    A survey approval rate rises from 21%\displaystyle 21\%21% to 31%\displaystyle 31\%31%. What is the increase in PERCENTAGE POINTS?

    Practise this exact problem →
Open stage PSAT 3.6 in the student workspace →
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Data Analysis: Evidence & Predictions: lessons and practice | Numerive Math