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PSAT/NMSQT Math / LEVEL 2 · DIFFICULTY 3/5
Advanced Math: Expressions & Functions
Connect equivalent expressions, nonlinear solutions and function models.
Choose a node to explore its lesson.
- MINI QUEST PSAT 2.1Rational Exponents & RadicalsRead the lesson
- MINI QUEST PSAT 2.2Quadratic Formula & Completing the SquareRead the lesson
- MINI QUEST PSAT 2.3Rational Equations & Domain RestrictionsRead the lesson
- MINI QUEST PSAT 2.4Radical Equations & Extraneous RootsRead the lesson
- MINI QUEST PSAT 2.5Lines & Parabolas: Nonlinear SystemsRead the lesson
- MINI QUEST PSAT 2.6Exponential Growth, Decay & TablesRead the lesson
STAGE PSAT 2.1 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Rational Exponents & Radicals
Goal: Rewrite roots as fractional powers and simplify equivalent expressions with valid domain restrictions.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
SAT extension: rational exponents and radical rewriting are enrichment beyond the PSAT equivalent-expression requirements.
Make sense of the idea
For positive a, means the nth root of a, raised to power m. The denominator names the root; the numerator names the power.
Choose a method
For , . When multiplying powers with the same base, add exponents. Do not add the bases.
Check and interpret
Over real numbers, even roots require nonnegative radicands. The principal square root is nonnegative: , not always x. Keep denominator restrictions when simplifying rational expressions.
Evaluate .
- The cube root of 64 is 4.
- .
16
A positive-input model contains . What is the exponent of x after combining the factors?
- .
- The combined power is , so the exponent is 1.
1
Common pitfalls
Possible mix-up: A negative exponent makes the result negative.
It takes a reciprocal. A positive base remains positive.
Possible mix-up: always equals x.
It equals ; test a negative value of x.
Explain it to yourself
In rational exponents & radicals, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
Evaluate .
Evaluate .
Evaluate when .
For , an expression contains . What is the exponent of x after combining the factors?
A scaling rule requires evaluating .
A model has multiplier .
A distance calculation contains when .
A positive-input model contains . What is the exponent of x after combining the factors?
STAGE PSAT 2.2 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Quadratic Formula & Completing the Square
Goal: Choose a quadratic-solving method, retain both roots, and interpret the discriminant.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
Parent quadratic: . Explore the parabola, then use the worked examples below to connect it to solutions and intersections.
AN EQUATION IS A RULE FOR MAKING POINTS
Change the rule. Watch the graph.
Pick an x value. The rule tells you its y value. A point (x, y) shows both numbers together. Drag across the graph or use the point slider. This is an adjustable learning example; use the coefficients in your own practice question when solving it.
Parent equation:
Start with . Complete the square: . The new vertex is (1, -4). The first coordinate gives the horizontal shift and the second gives the vertical shift. Multiply vertical distances from the vertex by 1.
Teal moving graph:
Blue:
Moving point: (-4, 16)
Teal shows the current transformation. Blue is the target. At they coincide; intermediate graphs are learning frames, not additional solutions.
Dashed gray: parent equation. Blue: current equation. View: −10 to 10 on both axes. The graph continues beyond this window. Purple marks your selected point.
The term makes the change in y vary with x. This parabola opens upward because a is positive.
| x | Substitute into the rule | y |
|---|---|---|
| -1 | 0 | |
| 0 | -3 | |
| 1 | -4 |
Make sense of the idea
Write with . The quadratic formula is . The denominator 2a divides the entire numerator.
Choose a method
To complete the square in , add . Add it to both sides. For example, becomes , so or −7.
Check and interpret
The discriminant counts real roots: gives two, gives one repeated root, gives none. A context can rule out a negative length without deleting it from the algebraic equation. Parent equation: .
Solve . Use the quadratic formula to find the larger real root.
- , so .
- gives 4 and . The larger root is 4.
4
A design equation is . Find c so that it has exactly one real solution.
- .
- ; then .
36
Common pitfalls
Possible mix-up: Taking a square root gives only the positive branch.
An equation with has z = ±.
Possible mix-up: Only c is divided by 2a.
In the quadratic formula the entire numerator is divided by 2a.
Explain it to yourself
In quadratic formula & completing the square, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
Solve . Use the quadratic formula to find the larger real root.
Complete the square to solve . Find the larger root.
How many real roots does have? Enter the number of real roots.
The equation is . Find c so that it has exactly one real solution.
A model reaches zero when . Use the quadratic formula to find the larger real root.
A trajectory equation reduces to . Find the larger root.
A height model would reach zero at a real root of ? Enter the number of real roots.
A design equation is . Find c so that it has exactly one real solution.
STAGE PSAT 2.3 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Rational Equations & Domain Restrictions
Goal: Solve equations with variable denominators and reject values outside the original domain.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
Make sense of the idea
First list every value that makes an original denominator zero. These values are forbidden even if a factor later cancels.
Choose a method
Multiply both sides by a common denominator only on the allowed domain. Solve the resulting equation, then substitute every candidate into the original equation.
Check and interpret
An equation can reduce to a contradiction, an identity with excluded points, or a finite set of valid roots. A canceled factor does not erase an original hole in the domain.
Solve . Find x.
- .
- , whose denominator is 6, not zero.
10
A simplified sensor model is . Which value of x remains excluded after simplification?
- gives .
- Although the expression simplifies to , the value −7 remains excluded.
-7
Common pitfalls
Possible mix-up: A canceled denominator can safely be zero.
The original expression is still undefined there.
Possible mix-up: Every root after clearing denominators is valid.
Check the original equation and excluded values.
Explain it to yourself
In rational equations & domain restrictions, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
Solve . Find x.
Consider . How many real solutions does the ORIGINAL equation have?
An equation uses . Solve for x.
The expression is . Which value of x remains excluded after simplification?
A rate model requires . Find x.
A calibration equality is . How many real solutions does the ORIGINAL equation have?
A work-rate equation uses . Solve for x.
A simplified sensor model is . Which value of x remains excluded after simplification?
STAGE PSAT 2.4 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Radical Equations & Extraneous Roots
Goal: Use the sign and domain of a square root before squaring, then check each candidate in the original equation.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
Make sense of the idea
The principal square root is nonnegative and is real only if . In , v must also be nonnegative.
Choose a method
Isolate the radical before squaring. Squaring can lose sign information, so it can introduce candidates that never satisfied the original equation.
Check and interpret
Substitute every candidate back into the unsquared equation. If the left side is a nonnegative root while the right side is negative, reject that candidate.
Solve . Find x.
- .
- ; substitution gives .
21
A side-length condition is . Find x.
- , so .
- . Substitution checks both the radicand and sign.
Common pitfalls
Possible mix-up: Squaring preserves all information.
For instance but .
Possible mix-up: A negative right side can equal a principal square root.
A principal square root is nonnegative.
Explain it to yourself
In radical equations & extraneous roots, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
Solve . Find x.
How many real solutions satisfy ? Enter the number of solutions.
Solve . Find the valid real solution.
Solve . Find x.
A distance model requires . Find x.
A sensor equation is ? Enter the number of solutions.
A length equation reduces to . Find the valid real solution.
A side-length condition is . Find x.
STAGE PSAT 2.5 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Lines & Parabolas: Nonlinear Systems
Goal: Find intersections by substitution and distinguish two, one and no real intersections.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
Two rules. Shared points.
Parent parabola: . The horizontal line is also a linear equation. A solution must lie on both graphs.
2 real intersections. (-2, 4) and (2, 4)
Set the outputs equal: . Both the positive and negative square roots work.
Make sense of the idea
Parent equations: for lines and for parabolas. An intersection must have the same x and y in both equations.
Choose a method
If both equations give y, set their right sides equal. Rearrange into a quadratic and solve. Substitute each x into either original equation to recover y.
Check and interpret
The quadratic discriminant tells you whether the line crosses the parabola twice, touches once, or misses it. The number of intersections is not automatically two.
Find intersections of and . What is the smaller x-coordinate?
- .
- The x-values are 4 and 6; the smaller is 4. The corresponding point is (4, 16).
4
A rectangle has area and . What is the smaller possible value of x?
- , so .
- x is 5 or 8; the smaller is 5.
5
Common pitfalls
Possible mix-up: An x-value alone is the full intersection point.
Find its corresponding y-value too.
Possible mix-up: Every line crosses a parabola twice.
A line can touch once or have no real intersection.
Explain it to yourself
In lines & parabolas: nonlinear systems, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
Find intersections of and . What is the smaller x-coordinate?
The line and parabola have how many real intersection points?
The curves and meet. What is the y-coordinate of their intersection?
Two quantities obey and . What is the smaller possible value of x?
A curved track and straight path follow and . What is the smaller x-coordinate?
A horizontal platform and parabola have how many real intersection points?
A line just touches a curved path and at one point. What is the y-coordinate of their intersection?
A rectangle has area and . What is the smaller possible value of x?
STAGE PSAT 2.6 · 8 PRACTICE PROBLEMS · 4 NEW-CONTEXT APPLICATIONS
Exponential Growth, Decay & Tables
Goal: Build and interpret exponential models from rates or tables, including decay and different time units.
Before you begin: Read the problem carefully and use the linked foundation lessons when a term or operation is unfamiliar.
Make sense of the idea
In , is the initial value and b is the factor for one unit of t. Growth of r as a decimal uses ; decay uses .
Choose a method
Equal time steps have equal ratios in an exponential model; a linear model has equal differences. Check that the time steps are equal before comparing.
Check and interpret
If a process doubles every 3 hours and t is hours, use . The denominator converts elapsed hours into the number of doubling periods. Parent family: , and .
A quantity starts at 400 and grows by each year. Find its value after 2 years.
- .
- The value is 576. The increase is compounded, not two increases on the original base.
576
A sensor gives values 5, 15, 45 at times 0, 1, 2. Assuming an exponential model, predict its value at time 3.
- The ratios are and .
- The next value is ; unequal differences distinguish this from a linear model.
135
Common pitfalls
Possible mix-up: decrease uses factor 0.20.
It retains , so the factor is 0.80.
Possible mix-up: Doubling every 3 hours means exponent 3t.
The number of periods is .
Explain it to yourself
In exponential growth, decay & tables, what information determines your method, and how can you check whether your result fits the original conditions?
Preview the eight practice prompts
A quantity starts at 200 and grows by each year. Find its value after 2 years.
A quantity keeps of its amount each hour. It starts at 300. How much remains after 2 hours?
A model doubles every 3 hours, starting at 4. What is its amount after 9 hours?
A function gives values 2, 6, 18 at times 0, 1, 2. Assuming an exponential model, predict its value at time 3.
A habitat population starts at 300 and grows by each year. Find its value after 2 years.
A filter retains of its amount each hour. It starts at 400. How much remains after 2 hours?
A culture doubles every 3 hours, starting at 5. What is its amount after 9 hours?
A sensor gives values 3, 9, 27 at times 0, 1, 2. Assuming an exponential model, predict its value at time 3.

