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Precalculus / LEVEL 4 · DIFFICULTY 4/5
Matrices and Space
Measure orientation and describe planes.
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STAGE PC 4.1 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS
Determinants and Area
Useful preparation: Dot Products
Goal: Understand and apply determinants and area.
Before you begin: Dot Products
Understand the idea
matrix sends the coordinate basis vectors to its columns. The signed area of their parallelogram is its determinant, describing area scaling and orientation.
Choose and carry out a method
Compute for rows (a,b) and (c,d). Use the absolute value for ordinary area and preserve the sign when orientation is requested.
Check the reasoning
Swapping columns changes the sign. Proportional columns give zero determinant because the parallelogram collapses onto a line.
Find the determinant of the matrix with rows (3,2) and (2,5).
- The determinant measures oriented area of the column parallelogram.
- .
- The signed scale factor is 11; ordinary area scales by its absolute value.
11
Find the determinant of the matrix with rows (4,3) and (2,6).
- The determinant measures oriented area of the column parallelogram.
- .
- The signed scale factor is 18; ordinary area scales by its absolute value.
18
Common pitfalls
Possible mix-up: The determinant always equals unsigned area.
Its sign records orientation; unsigned area uses its absolute value.
Possible mix-up: A correct numerical answer alone explains the method.
State the governing relationship and check the conditions described above.
Explain it to yourself
What geometric information does a zero determinant reveal?
Preview the eight practice prompts
Find the determinant of the matrix with rows (6,5) and (2,8).
Find the determinant of the matrix with rows (7,6) and (2,9).
Find the determinant of the matrix with rows (8,7) and (2,10).
Find the determinant of the matrix with rows (9,8) and (2,11).
Find the determinant of the matrix with rows (10,9) and (2,12).
Find the determinant of the matrix with rows (11,10) and (2,13).
A linear transformation of the plane sends (1,0) to (12,2) and (0,1) to (11,14). Find its signed area scale factor.
A linear transformation of the plane sends (1,0) to (13,2) and (0,1) to (12,15). Find its signed area scale factor.
STAGE PC 4.2 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS
Cross Products in Space
Useful preparation: Determinants and Area
Goal: Understand and apply cross products in space.
Before you begin: Determinants and Area
Understand the idea
The cross product in three dimensions is perpendicular to both input vectors. Its direction follows their order, while its magnitude gives the area of the spanned parallelogram.
Choose and carry out a method
For the z-component, use ᵧ−uᵧ. Keep in that order and enter only the component requested.
Check the reasoning
Reversing the vector order negates every component. A full computed cross product should have zero dot product with each input.
For and , find the z-component of .
- Expand the cross product in the stated order.
- ᵧ-uᵧ.
- The z-component is 12. Reversing the vectors reverses its sign.
12
For and , find the z-component of .
- Expand the cross product in the stated order.
- ᵧ-uᵧ.
- The z-component is 22. Reversing the vectors reverses its sign.
22
Common pitfalls
Possible mix-up: Reversing u and v preserves the cross product.
It preserves magnitude but reverses direction.
Possible mix-up: A correct numerical answer alone explains the method.
State the governing relationship and check the conditions described above.
Explain it to yourself
How could dot products check a complete cross-product calculation?
Preview the eight practice prompts
For and , find the z-component of .
For and , find the z-component of .
For and , find the z-component of .
For and , find the z-component of .
For and , find the z-component of .
For and , find the z-component of .
Two vectors and span an oriented surface. Find the z-component of its area vector .
Two vectors and span an oriented surface. Find the z-component of its area vector .
STAGE PC 4.3 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS
Planes and Normal Vectors
Useful preparation: Cross Products in Space
Goal: Understand and apply planes and normal vectors.
Before you begin: Cross Products in Space
Understand the idea
A normal vector is perpendicular to every displacement lying in a plane. Dotting the normal with the displacement from one known point therefore gives zero.
Choose and carry out a method
Form . Expand to a linear equation and substitute the requested horizontal coordinates to solve for height.
Check the reasoning
The given point must satisfy the plane equation. A nonzero z coefficient allows a unique height for each specified x and y.
A plane with normal (2,-3,4) passes through (3,4,5). At and , what is z on the plane?
- A normal vector is perpendicular to every displacement within the plane.
- . Substitute , .
- . This value satisfies the same plane equation.
2
A plane with normal (2,-3,4) passes through (4,5,6). At and , what is z on the plane?
- A normal vector is perpendicular to every displacement within the plane.
- . Substitute , .
- . This value satisfies the same plane equation.
3
Common pitfalls
Possible mix-up: The normal vector lies along the plane.
It points perpendicular to every direction within the plane.
Possible mix-up: A correct numerical answer alone explains the method.
State the governing relationship and check the conditions described above.
Explain it to yourself
Why do multiplying all plane coefficients by the same nonzero number describe the same plane?
Preview the eight practice prompts
A plane with normal (2,-3,4) passes through (6,7,8). At and , what is z on the plane?
A plane with normal (2,-3,4) passes through (7,8,9). At and , what is z on the plane?
A plane with normal (2,-3,4) passes through (8,9,10). At and , what is z on the plane?
A plane with normal (2,-3,4) passes through (9,10,11). At and , what is z on the plane?
A plane with normal (2,-3,4) passes through (10,11,12). At and , what is z on the plane?
A plane with normal (2,-3,4) passes through (11,12,13). At and , what is z on the plane?
A flat ramp has normal (2,-3,4) and contains (12,13,14). Find its height z above the horizontal location (15,11).
A flat ramp has normal (2,-3,4) and contains (13,14,15). Find its height z above the horizontal location (16,12).

