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Prealgebra / LEVEL 2 · DIFFICULTY 1/5

Powers & Exponent Structure

Reason about repeated multiplication, exponent laws and reciprocal powers.

3 stages · 24 practice problems · two 6-question assessment forms

Choose an island to read its lesson.

  1. 1MINI QUEST 2.1Powers, Signs & GroupingRead the lesson
  2. 2MINI QUEST 2.2Products, Quotients & Powers of PowersRead the lesson
  3. 3MINI QUEST 2.3Zero & Negative ExponentsRead the lesson
  4. LEVEL CHECKCastle challenge

    6 questions across this level.

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STAGE 2.1 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Powers, Signs & Grouping

Useful preparation: Signed Numbers & Order of Operations

The idea to remember

An exponent applies to its base, including a minus sign only when the sign is inside the base's parentheses.

Remember with 2 flashcards →

Goal: Distinguish a negative base from a negative sign outside a power.

Before you begin: Before starting, explain one example from each prerequisite. If an idea is unfamiliar, follow the prerequisite lesson links.

An exponent counts equal factors

For a positive integer n, a to the power n is a product of n copies of a. The exponent does not mean multiply a by n.

a3=a×a×a\displaystyle a^{3} = a \times a \times aa3=a×a×a

Group the base explicitly

Parentheses make a negative number the base. Without parentheses, a leading minus is applied after the power.

(−4)2=16\displaystyle \left(-4\right)^{2} = 16(−4)2=16; −42=−16\displaystyle -4^{2} = -16−42=−16

Use parity to predict the sign

An even number of negative factors has positive product. An odd number has negative product. Predicting the sign gives a useful check.

(−a)2n=a2n\displaystyle \left(-a\right)^{2n} = a^{2n}(−a)2n=a2n
WORKED EXAMPLE 1

Evaluate (−3)4−32\displaystyle \left(-3\right)^{4} - 3^{2}(−3)4−32.

  1. Four negative factors give a positive 81.
  2. The second power is 9; subtract it.

72

WORKED EXAMPLE 2

A colony triples each hour. It starts with 2 cells. How many after four hours?

  1. Four rounds of tripling multiply by 34\displaystyle 3^{4}34.
  2. 2×81=162\displaystyle 2 \times 81 = 1622×81=162.

162

Common pitfalls

Possible mix-up: 53\displaystyle 5^{3}53 is 15.

53=5×5×5=125\displaystyle 5^{3} = 5 \times 5 \times 5 = 12553=5×5×5=125.

Possible mix-up: −62\displaystyle -6^{2}−62 is 36.

The power acts before the leading minus: −62=−36\displaystyle -6^{2} = -36−62=−36.

Explain it to yourself

Compare (−2)5\displaystyle \left(-2\right)^{5}(−2)5 and −25\displaystyle -2^{5}−25. Why do they agree even though the grouping differs?

Discuss together

Have the learner write the repeated product and predict its sign before using a calculator.

Preview the eight practice prompts
  1. Problem 1

    Compute 43\displaystyle 4^{3}43.

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  2. Problem 2

    Compute (−5)2\displaystyle \left(-5\right)^{2}(−5)2.

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  3. Problem 3

    Compute −52\displaystyle -5^{2}−52, where the minus is outside the power.

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  4. Problem 4

    Compute (−2)5\displaystyle \left(-2\right)^{5}(−2)5.

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  5. Problem 5

    Evaluate 24+32×2\displaystyle 2^{4} + 3^{2} \times 224+32×2.

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  6. Problem 6

    How many negative integers x satisfy x2=49\displaystyle x^{2} = 49x2=49?

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  7. Problem 7New context

    A digital pattern starts with 5 lights. Each stage doubles the number. How many lights are present after six stages?

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  8. Problem 8New context

    A puzzle awards 32\displaystyle 3^{2}32 points for each of four clues and subtracts 23\displaystyle 2^{3}23 points once. What score results?

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Open stage 2.1 in the student workspace →

STAGE 2.2 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Products, Quotients & Powers of Powers

Useful preparation: Powers, Signs & Grouping

The idea to remember

Multiply powers with the same base by adding exponents; a power of a power multiplies exponents.

Remember with 2 flashcards →

Goal: Count factors to justify exponent rules for a common base.

Before you begin: Before starting, explain one example from each prerequisite. If an idea is unfamiliar, follow the prerequisite lesson links.

Products join factor lists

When powers have the same base, multiplication joins their repeated factors, so exponents add. Different bases need other reasoning.

am an=am+n\displaystyle a^{m}\, a^{n} = a^{m+n}aman=am+n

Quotients cancel factors

For a nonzero base, divide powers by canceling equal factors. The difference of the exponents records what remains.

am÷an=am−n\displaystyle a^{m} \div a^{n} = a^{m-n}am÷an=am−n

A power of a power repeats a whole group

Taking the nth power of am\displaystyle a^{m}am creates n groups of m factors; the total count is mn. A product raised to a power repeats each factor.

(am)n=amn\displaystyle \left(a^{m}\right)^{n} = a^{mn}(am)n=amn; (ab)n=an bn\displaystyle \left(ab\right)^{n} = a^{n}\, b^{n}(ab)n=anbn
WORKED EXAMPLE 1

Write (23)4×22\displaystyle \left(2^{3}\right)^{4} \times 2^{2}(23)4×22 as 2 to a single power.

  1. The nested power contributes 3×4=12\displaystyle 3 \times 4 = 123×4=12 factors of 2.
  2. The final product adds 2 more factors.

214\displaystyle 2^{14}214

WORKED EXAMPLE 2

Compute 56÷54\displaystyle 5^{6} \div 5^{4}56÷54.

  1. Cancel four factors of 5 from numerator and denominator.
  2. Two factors remain, giving 52\displaystyle 5^{2}52.

25

Common pitfalls

Possible mix-up: a3+a4\displaystyle a^{3} + a^{4}a3+a4 equals a7\displaystyle a^{7}a7.

The exponent addition rule is for multiplication, not addition.

Possible mix-up: (a2)3\displaystyle \left(a^{2}\right)^{3}(a2)3 equals a5\displaystyle a^{5}a5.

There are three groups of two factors, so the exponent is 6.

Explain it to yourself

Use repeated factors to explain why exponent multiplication appears for a power of a power.

Discuss together

Ask for the base first. Applying a correct rule to different bases is a frequent source of errors.

Preview the eight practice prompts
  1. Problem 1

    Write 34×32=3n\displaystyle 3^{4} \times 3^{2} = 3^{n}34×32=3n. Find n.

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  2. Problem 2

    Write 78÷73=7n\displaystyle 7^{8} \div 7^{3} = 7^{n}78÷73=7n. Find n.

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  3. Problem 3

    Write (52)4=5n\displaystyle \left(5^{2}\right)^{4} = 5^{n}(52)4=5n. Find n.

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  4. Problem 4

    Compute 27÷24\displaystyle 2^{7} \div 2^{4}27÷24.

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  5. Problem 5

    Write (32×34)3=3n\displaystyle \left(3^{2} \times 3^{4}\right)^{3} = 3^{n}(32×34)3=3n. Find n.

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  6. Problem 6

    Is 23+24\displaystyle 2^{3} + 2^{4}23+24 equal to 27\displaystyle 2^{7}27? Enter yes or no.

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  7. Problem 7New context

    A grid has 24\displaystyle 2^{4}24 rows and 26\displaystyle 2^{6}26 columns. If it has 2n\displaystyle 2^{n}2n cells, what is n?

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  8. Problem 8New context

    A drive contains 39\displaystyle 3^{9}39 equal files. A package holds 34\displaystyle 3^{4}34 files. If the number of full packages is 3n\displaystyle 3^{n}3n, find n.

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Open stage 2.2 in the student workspace →

STAGE 2.3 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Zero & Negative Exponents

Useful preparation: Products, Quotients & Powers of Powers · Division, Reciprocals & Zero

The idea to remember

For a≠0\displaystyle a \ne 0a=0, a0=1\displaystyle a^{0} = 1a0=1 and a−n=1an\displaystyle a^{-n} = \frac{1}{a^{n}}a−n=an1​. A negative exponent does not make the value negative.

Remember with 2 flashcards →

Goal: Extend exponent patterns to one and reciprocal values.

Before you begin: Before starting, explain one example from each prerequisite. If an idea is unfamiliar, follow the prerequisite lesson links.

A zero exponent produces the multiplicative identity

For a nonzero base, anan=1\displaystyle \frac{a^{n}}{a^{n}} = 1anan​=1. The exponent quotient pattern gives a0\displaystyle a^{0}a0, so a0\displaystyle a^{0}a0 must be 1. This argument does not define 00\displaystyle 0^{0}00.

a0=1\displaystyle a^{0} = 1a0=1 for a≠0\displaystyle a \ne 0a=0

Stepping down divides by the base

Each step downward in an exponent divides by the base. Continuing below zero produces reciprocal powers, not negative values.

a−n=1an\displaystyle a^{-n} = \frac{1}{a^{n}}a−n=an1​ for a≠0\displaystyle a \ne 0a=0

Keep sign and exponent separate

A negative exponent changes reciprocal structure. The sign of the base still determines the sign of an odd or even power.

(−2)−3=−18\displaystyle \left(-2\right)^{-3} = \frac{-1}{8}(−2)−3=8−1​
WORKED EXAMPLE 1

Evaluate 3−2+30\displaystyle 3^{-2} + 3^{0}3−2+30.

  1. 3−2=19\displaystyle 3^{-2} = \frac{1}{9}3−2=91​, while 30=1\displaystyle 3^{0} = 130=1.
  2. Combine 19+99\displaystyle \frac{1}{9} + \frac{9}{9}91​+99​.

109\displaystyle \frac{10}{9}910​

WORKED EXAMPLE 2

A magnifier rescales a length by 2−3\displaystyle 2^{-3}2−3. What fraction of the original length remains?

  1. The exponent indicates the reciprocal of 23\displaystyle 2^{3}23.
  2. Subtract exponents first: 2724=23=8\displaystyle \frac{2^{7}}{2^{4}} = 2^{3} = 82427​=23=8.

18\displaystyle \frac{1}{8}81​

Common pitfalls

Possible mix-up: a0\displaystyle a^{0}a0 is 0.

For nonzero a, a0\displaystyle a^{0}a0 is 1.

Possible mix-up: 4−2\displaystyle 4^{-2}4−2 is −16.

The negative exponent means reciprocal: 116\displaystyle \frac{1}{16}161​.

Explain it to yourself

Explain the difference between −32\displaystyle -3^{2}−32, (−3)2\displaystyle \left(-3\right)^{2}(−3)2 and 3−2\displaystyle 3^{-2}3−2.

Discuss together

Look for correct handling of both reciprocal and sign; these are separate decisions.

Preview the eight practice prompts
  1. Problem 1

    Compute 120\displaystyle 12^{0}120.

    Practise this exact problem →
  2. Problem 2

    Compute 2−4\displaystyle 2^{-4}2−4. Enter a fraction.

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  3. Problem 3

    Compute (−3)−3\displaystyle \left(-3\right)^{-3}(−3)−3.

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  4. Problem 4

    Compute 53×5−4\displaystyle 5^{3} \times 5^{-4}53×5−4.

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  5. Problem 5

    Compute (23)−2\displaystyle \left(\frac{2}{3}\right)^{-2}(32​)−2.

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  6. Problem 6

    Write 10−3÷10−5=10n\displaystyle 10^{-3} \div 10^{-5} = 10^{n}10−3÷10−5=10n. Find n.

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  7. Problem 7New context

    A map scale multiplies every length by 3−2\displaystyle 3^{-2}3−2. A road measures 72 units before scaling. How long is it afterward?

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  8. Problem 8New context

    A sensor multiplies a signal by 2−3\displaystyle 2^{-3}2−3, then another circuit multiplies it by 25\displaystyle 2^{5}25. What is the combined numerical multiplier?

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Open stage 2.3 in the student workspace →
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∑ Numerive

Learn

HomeTry a questionMy questsLearning SearchHomeworkUnderstand & rememberCurriculumFlashcardsUniversity

Exam preparation

Mock examsSATPSAT/NMSQTAMC 8 / 10 / 12

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My characterAchievementsFriendsStudy groups

Family & help

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Powers & Exponent Structure: lessons and practice | Numerive Math