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← Introduction to Geometry levels

Introduction to Geometry / LEVEL 3 · DIFFICULTY 3/5

Polygons and Circles

Reason about turns, arcs and intersecting chords.

3 stages · 24 practice problems · two 6-question assessment forms

Choose an island to read its lesson.

  1. 1MINI QUEST GEO 3.1Polygon Angle SumsRead the lesson
  2. 2MINI QUEST GEO 3.2Arcs and Central AnglesRead the lesson
  3. 3MINI QUEST GEO 3.3Intersecting ChordsRead the lesson
  4. LEVEL CHECKCastle challenge

    6 questions across this level.

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STAGE GEO 3.1 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Polygon Angle Sums

Useful preparation: Right-Triangle Distance

The idea to remember

Triangulating a simple n-gon from a suitable vertex yields the angle-sum formula (n−2) 180∘\displaystyle \left(n - 2\right)\, 180^{\circ}(n−2)180∘.

Remember with 2 flashcards →

Goal: Understand and apply polygon angle sums.

Before you begin: Right-Triangle Distance

Understand the idea

Drawing diagonals from one vertex divides a convex n-sided polygon into n−2\displaystyle n - 2n−2 triangles. Adding their angle sums counts each polygon interior angle exactly once.

interior sum=(n−2)⋅180∘\displaystyle \left(n - 2\right) \cdot 180^{\circ}(n−2)⋅180∘

Choose and carry out a method

Count the sides, subtract two, and multiply by 180∘\displaystyle 180^{\circ}180∘. Regularity is unnecessary for the total but is needed to divide equally among vertices.

Check the reasoning

A triangle gives 180∘\displaystyle 180^{\circ}180∘ and a quadrilateral gives 360∘\displaystyle 360^{\circ}360∘. Each extra side adds one triangle to the construction.

WORKED EXAMPLE 1

Find the sum of the interior angles of a convex 6-gon, in degrees.

  1. Draw diagonals from one vertex to divide a convex polygon into triangles.
  2. A 6-gon contains 4 triangles in this division.
  3. The angle sum is 4⋅180=720∘\displaystyle 4 \cdot 180 = 720^{\circ}4⋅180=720∘.

720

WORKED EXAMPLE 2

Find the sum of the interior angles of a convex 7-gon, in degrees.

  1. Draw diagonals from one vertex to divide a convex polygon into triangles.
  2. A 7-gon contains 5 triangles in this division.
  3. The angle sum is 5⋅180=900∘\displaystyle 5 \cdot 180 = 900^{\circ}5⋅180=900∘.

900

Common pitfalls

Possible mix-up: There are n triangles in the construction.

A fan from one vertex creates n−2\displaystyle n - 2n−2 triangles.

Possible mix-up: A correct numerical answer alone explains the method.

State the governing relationship and check the conditions described above.

Explain it to yourself

Why does a polygon’s total not determine each separate angle?

Discuss together

Invite your learner to explain: Why does a polygon’s total not determine each separate angle? Use the worked examples to discuss their reasoning.

Preview the eight practice prompts
  1. Problem 1

    Find the sum of the interior angles of a convex 9-gon, in degrees.

    Practise this exact problem →
  2. Problem 2

    Find the sum of the interior angles of a convex 10-gon, in degrees.

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  3. Problem 3

    Find the sum of the interior angles of a convex 11-gon, in degrees.

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  4. Problem 4

    Find the sum of the interior angles of a convex 12-gon, in degrees.

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  5. Problem 5

    Find the sum of the interior angles of a convex 13-gon, in degrees.

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  6. Problem 6

    Find the sum of the interior angles of a convex 14-gon, in degrees.

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  7. Problem 7New context

    A convex garden border has 15 straight sides. What is the sum of its interior corner angles in degrees?

    Practise this exact problem →
  8. Problem 8New context

    A convex garden border has 16 straight sides. What is the sum of its interior corner angles in degrees?

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Open stage GEO 3.1 in the student workspace →

STAGE GEO 3.2 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Arcs and Central Angles

Useful preparation: Polygon Angle Sums

The idea to remember

Arc length is radius times angle in radians, or θ360\displaystyle \frac{\theta}{360}360θ​ times the circumference in degrees.

Remember with 2 flashcards →

Goal: Understand and apply arcs and central angles.

Before you begin: Polygon Angle Sums

Understand the idea

A central angle picks the same fraction of a circle’s circumference as its fraction of a full 360∘\displaystyle 360^{\circ}360∘ turn. The radius scales circumference linearly.

s=(θ360∘)⋅2 π r\displaystyle s = \left(\frac{\theta}{360^{\circ}}\right) \cdot 2\, \pi\, rs=(360∘θ​)⋅2πr

Choose and carry out a method

Compute angle/360 times 2 π r\displaystyle 2\, \pi\, r2πr. When the prompt asks for the coefficient of π\displaystyle \piπ, enter the rational coefficient only.

Check the reasoning

A 180∘\displaystyle A\, 180^{\circ}A180∘ arc is half the circumference. Arc length has length units; a sector’s area has square units.

WORKED EXAMPLE 1

A circle has radius 4 and a central angle of 60∘\displaystyle 60^{\circ}60∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

  1. Use the central angle as a fraction of a full revolution.
  2. Arc length=(60360)⋅2 π⋅4\displaystyle \left(\frac{60}{360}\right) \cdot 2\, \pi \cdot 4(36060​)⋅2π⋅4.
  3. The coefficient of π\displaystyle \piπ is 43\displaystyle \frac{4}{3}34​. This is an arc length, not a sector area.

43\displaystyle \frac{4}{3}34​

WORKED EXAMPLE 2

A circle has radius 5 and a central angle of 90∘\displaystyle 90^{\circ}90∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

  1. Use the central angle as a fraction of a full revolution.
  2. Arc length=(90360)⋅2 π⋅5\displaystyle \left(\frac{90}{360}\right) \cdot 2\, \pi \cdot 5(36090​)⋅2π⋅5.
  3. The coefficient of π\displaystyle \piπ is 52\displaystyle \frac{5}{2}25​. This is an arc length, not a sector area.

52\displaystyle \frac{5}{2}25​

Common pitfalls

Possible mix-up: Use π r2\displaystyle \pi\, r^{2}πr2 to find arc length.

That measures an area; use circumference for an arc.

Possible mix-up: A correct numerical answer alone explains the method.

State the governing relationship and check the conditions described above.

Explain it to yourself

What changes if the radius doubles but the angle stays fixed?

Discuss together

Invite your learner to explain: What changes if the radius doubles but the angle stays fixed? Use the worked examples to discuss their reasoning.

Preview the eight practice prompts
  1. Problem 1

    A circle has radius 7 and a central angle of 150∘\displaystyle 150^{\circ}150∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

    Practise this exact problem →
  2. Problem 2

    A circle has radius 8 and a central angle of 30∘\displaystyle 30^{\circ}30∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

    Practise this exact problem →
  3. Problem 3

    A circle has radius 9 and a central angle of 60∘\displaystyle 60^{\circ}60∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

    Practise this exact problem →
  4. Problem 4

    A circle has radius 10 and a central angle of 90∘\displaystyle 90^{\circ}90∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

    Practise this exact problem →
  5. Problem 5

    A circle has radius 11 and a central angle of 120∘\displaystyle 120^{\circ}120∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

    Practise this exact problem →
  6. Problem 6

    A circle has radius 12 and a central angle of 150∘\displaystyle 150^{\circ}150∘. The intercepted arc length is k π\displaystyle k\, \pikπ. Find k.

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  7. Problem 7New context

    A wheel of radius 13 cm turns through 30∘\displaystyle 30^{\circ}30∘. A point on its rim travels k π\displaystyle k\, \pikπ cm along the circle. Find k.

    Practise this exact problem →
  8. Problem 8New context

    A wheel of radius 14 cm turns through 60∘\displaystyle 60^{\circ}60∘. A point on its rim travels k π\displaystyle k\, \pikπ cm along the circle. Find k.

    Practise this exact problem →
Open stage GEO 3.2 in the student workspace →

STAGE GEO 3.3 · 8 PRACTICE PROBLEMS · 2 NEW-CONTEXT APPLICATIONS

Intersecting Chords

Useful preparation: Arcs and Central Angles

The idea to remember

For two chords intersecting inside a circle, the products of the two segment lengths on each chord are equal.

Remember with 2 flashcards →

Goal: Understand and apply intersecting chords.

Before you begin: Arcs and Central Angles

Understand the idea

Two chords intersecting inside a circle form similar triangles. Corresponding side ratios imply that the two segment lengths on one chord have the same product as those on the other.

a⋅b=c⋅d\displaystyle a \cdot b = c \cdot da⋅b=c⋅d

Choose and carry out a method

Pair the two parts of each whole chord. Set their products equal and divide by the known segment next to the unknown one.

Check the reasoning

Keep segment lengths distinct from full chord lengths. The recovered segment must be positive and satisfy the product equation.

WORKED EXAMPLE 1

Two chords intersect inside a circle. One has segments 3 and 8; the other has segments 4 and x. Find the segment labeled x.

  1. For intersecting chords, the two segment products are equal.
  2. 3⋅8=4⋅x\displaystyle 3 \cdot 8 = 4 \cdot x3⋅8=4⋅x, so x=244\displaystyle x = \frac{24}{4}x=424​.
  3. The missing segment is 6; the two products agree.

6

WORKED EXAMPLE 2

Two chords intersect inside a circle. One has segments 4 and 10; the other has segments 5 and x. Find the segment labeled x.

  1. For intersecting chords, the two segment products are equal.
  2. 4⋅10=5⋅x\displaystyle 4 \cdot 10 = 5 \cdot x4⋅10=5⋅x, so x=405\displaystyle x = \frac{40}{5}x=540​.
  3. The missing segment is 8; the two products agree.

8

Common pitfalls

Possible mix-up: Multiply neighboring segments from different chords.

Each product uses the two pieces of one chord.

Possible mix-up: A correct numerical answer alone explains the method.

State the governing relationship and check the conditions described above.

Explain it to yourself

Sketch the similar triangles that explain the product relationship.

Discuss together

Invite your learner to explain: Sketch the similar triangles that explain the product relationship. Use the worked examples to discuss their reasoning.

Preview the eight practice prompts
  1. Problem 1

    Two chords intersect inside a circle. One has segments 6 and 14; the other has segments 7 and x. Find the segment labeled x.

    Practise this exact problem →
  2. Problem 2

    Two chords intersect inside a circle. One has segments 7 and 16; the other has segments 8 and x. Find the segment labeled x.

    Practise this exact problem →
  3. Problem 3

    Two chords intersect inside a circle. One has segments 8 and 18; the other has segments 9 and x. Find the segment labeled x.

    Practise this exact problem →
  4. Problem 4

    Two chords intersect inside a circle. One has segments 9 and 20; the other has segments 10 and x. Find the segment labeled x.

    Practise this exact problem →
  5. Problem 5

    Two chords intersect inside a circle. One has segments 10 and 22; the other has segments 11 and x. Find the segment labeled x.

    Practise this exact problem →
  6. Problem 6

    Two chords intersect inside a circle. One has segments 11 and 24; the other has segments 12 and x. Find the segment labeled x.

    Practise this exact problem →
  7. Problem 7New context

    Two straight supports, each joining two points on a circular frame, cross inside the circle. One support is split into 12 cm and 26 cm; the second has one piece 13 cm long. Find the other piece in centimeters.

    Practise this exact problem →
  8. Problem 8New context

    Two straight supports, each joining two points on a circular frame, cross inside the circle. One support is split into 13 cm and 28 cm; the second has one piece 14 cm long. Find the other piece in centimeters.

    Practise this exact problem →
Open stage GEO 3.3 in the student workspace →
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∑ Numerive

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HomeTry a questionMy questsLearning SearchHomeworkUnderstand & rememberCurriculumFlashcardsUniversity

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Mock examsSATPSAT/NMSQTAMC 8 / 10 / 12

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Polygons and Circles: lessons and practice | Numerive Math